std::chrono::operator+, std::chrono::operator- (std::chrono::year_month_weekday)
From cppreference.com
< cpp | chrono | year month weekday
| constexpr std::chrono::year_month_weekday operator+(const std::chrono::year_month_weekday& ymwd, const std::chrono::months& dm) noexcept; |
(1) | (since C++20) |
| constexpr std::chrono::year_month_weekday operator+(const std::chrono::months& dm, const std::chrono::year_month_weekday& ymwd) noexcept; |
(2) | (since C++20) |
| constexpr std::chrono::year_month_weekday operator+(const std::chrono::year_month_weekday& ymwd, const std::chrono::years& dy) noexcept; |
(3) | (since C++20) |
| constexpr std::chrono::year_month_weekday operator+(const std::chrono::years& dy, const std::chrono::year_month_weekday& ymwd) noexcept; |
(4) | (since C++20) |
| constexpr std::chrono::year_month_weekday operator-(const std::chrono::year_month_weekday& ymwd, const std::chrono::months& dm) noexcept; |
(5) | (since C++20) |
| constexpr std::chrono::year_month_weekday operator-(const std::chrono::year_month_weekday& ymwd, const std::chrono::years& dy) noexcept; |
(6) | (since C++20) |
1-2) Adds dm.count() months to the date represented by
ymwd. The result has the same year() and month() as std::chrono::year_month(ymwd.year(), ymwd.month()) + dm and the same weekday() and index() as ymwd.3-4) Adds dy.count() years to the date represented by
ymwd. The result is equivalent to std::chrono::year_month_weekday(ymwd.year() + dy, ymwd.month(), ymwd.weekday_indexed()).5) Subtracts dm.count() months from the date represented by
ymwd. Equivalent to ymwd + -dm.6) Subtracts dy.count() years from the date represented by
ymwd. Equivalent to ymwd + -dy.Notes
Even if ymwd.ok() is true, the resulting year_month_weekday may not represent a valid date if ymwd.index() is 5.